Voltage Drop Calculator
Calculate voltage drop over a wire run for single-phase or three-phase circuits, based on wire gauge, distance, and current.
Exceeds 3% recommended limit
How It Works
- 1
Pick wire gauge and material
Select the AWG size installed or proposed, and choose copper or aluminum. Aluminum is not rated below 12 AWG in most codes.
- 2
Enter length, current, voltage, and phase
Put in the one-way run length in feet, the load current in amps, the nominal circuit voltage, and whether the circuit is DC, single-phase, or three-phase.
- 3
Check the drop against the 3% guideline
Read the voltage drop in volts and percent, plus the voltage arriving at the load. The calculator flags drops over 3% as outside the NEC recommendation.
Voltage Drop: Why Long Runs Burn Out Motors
Run 100 feet of 12 AWG copper to a 20-amp load and you lose 7.7 volts. On a 120 V circuit that's a 6.4% drop, past the 3% NEC recommends, and enough to shave roughly 19% off an incandescent bulb's brightness and rob a motor of starting torque. Every foot of wire between the panel and the load is a small resistor pulling voltage out of the circuit. For DC and single-phase AC, voltage drop follows V = 2 × I × R × L. The factor of 2 accounts for the round trip through the hot and neutral conductors. Three-phase balanced circuits use V = √3 × I × Z × L on a line-to-line basis. Resistivity for copper is 1.68 × 10⁻⁸ Ω·m at 20 °C; aluminum is 2.82 × 10⁻⁸ Ω·m, giving aluminum about 59.6% of copper's conductivity. Metals get more resistive as they heat up. A conductor operating near its insulation rating at 75 °C runs about 22% higher resistance than the same wire at 20 °C, which is why calculators that ignore temperature systematically undersize wire. NEC Article 210.19 Informational Note No. 4 recommends no more than 3% drop on a branch circuit and no more than 5% combined feeder-plus-branch. These are recommendations, not enforceable code in most sections, but motors, LED drivers, and electronic equipment all have real-world tolerances below those limits. The simplest fix is to go up one gauge. Each step drops resistance by roughly 21%.
Common pitfalls
Using one-way distance on a single-phase circuit. The round-trip current flows through both the hot and the neutral, so the formula is V_drop = 2 x I x R_per_ft x L_one_way. Drop the 2 and a 100 ft run calculates at half its actual drop.
Mixing up line-to-line and line-to-neutral on three-phase. Balanced three-phase uses V_drop = √3 x I x Z x L on a line-to-line basis (no factor of 2). Unbalanced or single-phase lines pulled from a three-phase panel still use the 2 x L formula.
Ignoring conductor operating temperature. Copper resistance rises about 0.4% per °C. A conductor running at its 75 °C rating has 22% more resistance than the 20 °C table value, so a 3% calculated drop can become 3.7% at full load. Use the NEC Chapter 9 Table 8 resistances at the expected operating temperature, not the room-temperature values.
Assuming the 3% branch-circuit guideline is enforceable. NEC 210.19 Informational Note No. 4 (branch) and 215.2 (feeder) recommend 3% and 5% combined, but informational notes are not mandatory code. Motors, LED drivers, and electronic loads often need tighter margins than the recommendation.
Only sizing for ampacity. A 100 ft, 20 A run on 12 AWG meets ampacity but drops 6.4% at 120 V. Voltage drop is an independent check, and for long runs it almost always dictates wire size.
Frequently Asked Questions
How is voltage drop calculated?
For DC or single-phase AC: V_drop = 2 × L × I × R_per_ft, where the factor of 2 accounts for the round-trip current path (hot and neutral). For three-phase AC: V_drop = √3 × L × I × R_per_ft, reflecting the balanced three-phase relationship between line-to-line voltage and line current. R_per_ft comes from NEC Chapter 9 Table 8 (DC resistance at 75°C).
What is the maximum acceptable voltage drop?
NEC Article 210.19 Informational Note No. 4 recommends no more than 3% drop on a branch circuit and no more than 5% total on the combined feeder and branch circuit. These are recommendations, not code requirements, but following them ensures motors start reliably, resistive loads deliver rated power, and sensitive electronics stay within their input-voltage window.
Why does three-phase drop less than single-phase for the same current?
The √3 factor (≈1.732) is smaller than the single-phase factor of 2. For the same wire, length, and current, three-phase voltage drop is √3/2 ≈ 86.6% of the single-phase drop. This is one reason three-phase distribution is used for long runs and large loads — it's inherently more efficient.
Does this include conductor reactance?
No. This tool uses DC resistance, which is accurate for small-to-medium gauges at 60 Hz. For large conductors (1/0 AWG and above) or for precise AC drop calculations, full impedance from NEC Chapter 9 Table 9 should be used. Reactance increases drop on inductive circuits and is power-factor dependent.
Why does aluminum drop more than copper?
Aluminum has about 61% the conductivity of copper, so its resistance per foot is roughly 1.6× higher for the same gauge. A 12 AWG copper wire has 1.93 Ω per 1000 ft; 12 AWG aluminum is 3.18 Ω per 1000 ft. For equal drop, aluminum must be one to two AWG sizes larger.
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